2x^2-8=504

Solution for 2x^2-8=504 equation:

2x^2-8=504

We move all terms to the left:

2x^2-8-(504)=0

We add all the numbers together, and all the variables

2x^2-512=0

a = 2; b = 0; c = -512;
Δ = b2-4ac
Δ = 02-4·2·(-512)
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4096}=64$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-64}{2*2}=\frac{-64}{4}
=-16
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+64}{2*2}=\frac{64}{4}
=16
$